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Given that HCF (306, 657) = 9, find LCM (306, 657).

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Given that HCF (306, 657) = 9, find LCM (306, 657).

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H.C.F × L.C.M = a × b 

(a, b) × (a, b) = a × b 

9 × x = 306 × 657 

x = \(\frac{306 \times 657}{9}\)

∴ x = 22338 

∴ L.C.M of (306, 657) = 22338

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