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Calculate the standard enthalpy of formation of CH3OH (l) from the following data: 

CH3OH (l) + 3/2O2 (g) → CO2 (g) + 2H2O (l); ∆rH0 = -726 KJ/mol 

C (s) + O2 (g) → CO2 (g) ; ∆CH0 = -393 KJ/mol 

H2 (g) + ½ O2 (g) → H2O (l); ∆f H0 = -286 KJ/mol

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