Given,
Depth of the cylindrical vessel = Height of the cylindrical vessel = h = 42 cm (common for both)
Inner diameter of the cylindrical vessel = 14 cm
So, the inner radius of the cylindrical vessel = r1 = 14/2 = 7 cm
Outer diameter of the cylindrical vessel = 16 cm
So, the outer radius of the cylindrical vessel = r2 = 16/2 = 8 cm
Now,
The volume of the cylindrical vessel
V = π(r22 – r12 ) x h
= π(82 – 72 ) x 42
= 22/7 x 15 x 42
V = 1980 cm3
Therefore, the total space between the two vessels is 1980 cm3, which is also the amount of cork dust required.