Given,
Height of the bucket (h) = 24 cm
Radius of the circular ends of the bucket 5 cm and 15 cm
So, r1 = 5 cm; r2 = 15 cm
Let ‘L’ be the slant height of the bucket
Then, we know that
Now,
Curved surface area of the bucket
= π(r1 + r2)l + πr12
= π(5 + 15)26 + π52
= π(520 + 25)
= 545π cm2
Therefore, the curved surface area of the bucket = 545π cm2.