Let R and r be the radii of the top and base of the bucket respectively,
Let h be its height.
Then, we have R = 20 cm, r = 10 cm, h = 30 cm
Capacity of the bucket = Volume of the frustum of the cone
= 1/3 π(R2 + r2 + R r )h
= 1/3 π(202 + 102 + 20 x 10 ) x 30
= 3.14 x 10 (400 + 100 + 200)
= 21980 cm3 = 21.98 litres
Now,
Surface area of the bucket = CSA of the bucket + Surface area of the bottom
= π l (R + r) + πr2
We know that,
l = √h2 + (R – r)2
= √[302 + (20 – 10)2] = √(900 + 100)
= √1000 = 31.62 cm
So,
The Surface area of the bucket = (3.14) x 31.62 x (20 + 10) + (3.14) x 102
= 2978.60 + 314
= 3292.60 cm2
Next, given that the cost of 1 litre milk = Rs 25
Thus, the cost of 21.98 litres of milk = Rs (25 x 21.98) = Rs 549.50