Given: σ0 = 2.6,
n = 20, S = 2, a=1%
H0: σ0 =2.6(Standard deviation is 2.6)
H1 : σ0 < 2.6 (Standard deviation less than 2.6) {Lower tailed test}
Under H0, the test statistic is :
= \(\frac{20 \times2^2}{(2.6)^2}\)
χ2cal = 11.8343
For (n- 1) = (20 – 1) = 19 d.f the lower tail critical value at 5% level of significance is K1 – 10.12;
Here χ2cal > K1
∴ H0 is accepted.
Conclusion: Standard deviation is 2.6.