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How can three resistors of resistances 2Ω, 3Ω, and 6Ω be connected to give a total resistance of (a) 4Ω, (b) 1Ω?

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In this diagram 2 resistors of resistance 3W and 3W are connected in parallel.

If 2Ω and 2Ω are connected in series 2Ω + 2Ω = 4Ω

∴ Total resistance = 4Ω

If resistors are connected in series

∴ Total resistance = 1Ω

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