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in Physics by (61.1k points)

Show how you would connect three resistors, each of resistance 6Ω, so that the combination has a resistance of (i) 9Ω, (ii) 4Ω.

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If resistors are connected in series 6Ω + 6Ω + 6Ω =18Ω This ia not correct

When they are connected in parallel

\(\frac{1}{6}+\frac{1}{6}+\frac{1}{6}\) = 3 This is also wrong,

i) When they are connected in parallel

Two 6Ω resistors are connected in parallel

If 3rd resistor of 6Ω and 3Ω are connected in series, it becomes 6Ω + 3Ω = 9Ω.

ii) When they are connected in series

Resistance = 6Ω + 6Ω

= 12Ω

If 3rd resistor 6Ω is connected to 12Ω in parallel

Total resistance = 4Ω.

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