Question

A proton projected in a magnetic field of 0.020T travels along a helical path of radius 5.0cm and pitch 20cm. Find the components of the velocity of the proton along and perpendicular to the magnetic field. Take the mass of the proton = 1.6 x 10^-27kg.

Answer 1

vector B = 0.020T M_P= 1.6 × 10^–27Kg

Pitch = 20cm = 2 × 10^–1m

Radius = 5cm = 5 × 10^–2m

We know for a helical path, the velocity of the proton has got two components θ_⊥& θ_H

= 0.6369 × 10⁵ ≈ 6.4 × 10⁴m/s