​ Two water taps together can fill a tank in 9(3/8) hours. The tap of larger diameter takes 10 hours less than ​

Question

Two water taps together can fill a tank in 9\(\frac{3}{8}\) hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank. .

Answer 1

Let the time required to fill up the tank for tap having larger diameter be ‘x’ Hr. 

For ‘x’ hour part of the tank filling is 1. 

For 9\(\frac{3}{8}\)hr. part of the tank filling ……….. ? 

i.e., \(\frac{75 \times1}{8x}\)part 

Time required for smaller diameter is = (x – 10)Hr. 

For (x – 10)Hr part of the tank filling is 1 

For  9\(\frac{3}{8}\)Hr. part of the tank is ………… ?

∴Time required for larger diameter, x = 25 Hr. 

∴ Time required for smaller diameter, = x – 10 = 15 Hr.