Let the Height of the broken part be ‘x’ m.
BC is the distance between the foot of the tree to the point where the top touches the ground.
In ⊥∆ABC, ∠B = 90°.
∴ Height of broken part of the tree, AB = x
∴ y = 2x = 2 × 4.62 y = 9.24 m.
Full height of the tree = x + y
∴ Height of the tree = x + y
= 4.62 + 9.24
= 13.86 m.