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The objective function and two solutions of an L.P.P. are : maxz = 200x + 100y and A (0, 5), B(10, 7).

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The objective function and two solutions of an L.P.P. are : maxz = 200x + 100y and A (0, 5), B(10, 7). Find the optimal value of z.

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For A (0,5): Max z =200(0)+ 100(5) 

z =500 

For B(10, 7): Max z =200(10)+100(7) 

z =2700 

The optimal value of z =2700.

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