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A manufacturer produces 2 products A and B which needs two machines P and Q. Product A requires 6 hours on machine P and 2 hours on machine Q. Product B requires 4 hours on machine P and 4 hours on machine Q. There are 100 hours of time available on machine P and 80 hours on machine Q. Profit earned by the manufacturer on selling one unit of A is Rs.10 and on selling one unit of B is Rs.15. Formulate L.P.P. ,

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Let x be the number of units of product A 

Sold and y be the number of units of product B sold

Then, the L.P.P is – 

Maximize Z = 10x + 15y 

Subject to 6x + 4y ≤100 

2x + 4y ≤ 80 

and x ≥ 0, y ≥ 0.

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