Fewpal
0 votes
11 views
in Statistics by (64.3k points)
edited by

For the following transportation problem, obtain the Initial basic feasible solution by:-  N.W.C.R and 

1 Answer

+1 vote
by (59.5k points)
selected by
 
Best answer

1. By N.W.CR:- Start allocating at north corner cell at the cell (1, 1): X11 = Min (a1 b1)

= min (5, 7) = 5

Here O1 is satisfied, next allocate at (2, 1) as: 

X21 = Min (a2, b1 – X11) = Min (8, 7-5) 

= Min (8, 2) = 2 

D1 satisfied and next allocation is made at (2, 2): 

X22 = Min (a2 – X21, b2

= Min (8-2, 9) 

= Min (6, 9) = 6

O2 availabilities are allocated, next allocate at (3, 2): X32 

= Min (a3, b32 – X22

= Min (7, 9 – 6) = Min (7, 3) = 3 

D2 Satisfied, next allocate at (3, 3) as: 

X33 = Min (a3 – X32, b3

= Min (7-3, 18) = min (4, 18) = 4 

O3 Satisfied, Allocate at (4, 3) as: 

X43 = Min (a4, b3 – X33

= Min (14, 18, -4) = Min (14,14) = 14

The Initial Basic feasible solution (I. B. F.S) is:

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...