Question

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.

Sodium carbonate + ethanoic acid ➝ sodium ethanoate + carbon dioxide + water

Answer 1

Sodium carbonate + ethanoic acid ➝ sodium ethanoate + carbon dioxide + water

5.3 + 6 ➝ 8.2 + 2.2 + 0.9

= 11.3 g → 11.3 g

Weight of reactants is equal to weight of products. This observation is in agreement with the law of conservation of mass.