5(7x+5)/3 – 23/3 = 13 – (4x-2)/3
By rearranging
(35x + 25)/3 + (4x – 2)/3 = 13 + 23/3
(35x + 25 + 4x – 2)/3 = (39+23)/3
(39x + 23)/3 = 62/3
By cross-multiplying
(39x + 23)3 = 62(3)
39x + 23 = 62
39x = 62 – 23
39x = 39
x = 1
Let us verify the given equation now,
5(7x+5)/3 – 23/3 = 13 – (4x-2)/3
By substituting the value of ‘x’ we get,
(35x + 25)/3 – 23/3 = 13 – (4x-2)/3
(35+25)/3 – 23/3 = 13 – (4-2)/3
60/3 – 23/3 = 13 – 2/3
(60-23)/3 = (39-2)/3
37/3 = 37/3
1 = 1
Hence, the given equation is verified.