We have,
(9x-7)/(3x+5) = (3x-4)/(x+6)
(9x-7)/(3x+5) – (3x-4)/(x+6) = 0
By taking LCM as (3x+5) (x+6)
((9x-7) (x+6) – (3x-4) (3x+5)) / (3x+5) (x+6) = 0
By cross-multiplying we get,
(9x-7) (x+6) – (3x-4) (3x+5) = 0
Upon expansion we get,
9x2 + 54x – 7x – 42 – (9x2 + 15x – 12x – 20) = 0
44x – 22 = 0
44x = 22
x = 22/44
= 2/4
= 1/2
Now let us verify the given equation,
(9x-7)/(3x+5) = (3x-4)/(x+6)
By substituting the value of ‘x’ we get,
(9(1/2) – 7) / (3(1/2) + 5) = (3(1/2) – 4) / ((1/2) + 6)
(9/2 – 7) / (3/2 + 5) = (3/2 – 4) / (1/2 + 6)
((9-14)/2) / ((3+10)/2) = ((3-8)/2) / ((1+12)/2)
-5/2 / 13/2 = -5/2 / 13/2
-5/13 = -5/13
Hence, the given equation is verified.