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in Trigonometry by (65.2k points)

From the top of a 7m. high building, the angle of elevation of the top of a cable tower is 60° and th angle of depression is its foot is 45°. Determine the height of the tower.

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Let the height of tower, PQ = h m. 

The height of building, AB = 7 m.

Angle of elevation, ∠PAR = 60° 

Angle of depression, ∠RAQ = 45° 

∠AQB = 45° (∵ Alternate angle) 

Let, BQ = AR = x m.

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