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in Probability by (65.2k points)

(i) A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that the bulb is defective ? 

(ii) Suppose the bulb drawn in (i) is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective ?

1 Answer

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Best answer

Out of 20 bulbs, contain 4 defective ones. (i) 

∴ Probability of defective bulb = \(\frac{4}{20}\)

(ii) Out of 20, one bulb is drawn at random from the lot then remaining bulbs = 19. 

Out of 19 bulbs, the bulbs which arc not defective = 19 – 4 = 15 

∴ The probability that the bulb is not defective, P(E) = \(\frac{15}{19}\)

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