Fewpal
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Find energy of each of the photons which
(i) correspond to light of frequency 3× 1015 Hz.
(ii) have wavelength of 0.50 Å.

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(i) Energy (E) of a photon is given by the expression,

E=hv

Where, h = Planck’s constant = 6.626 × 10–34 Js
ν = frequency of light = 3 × 1015 Hz
Substituting the values in the given expression of E:
E = (6.626 × 10–34) (3 × 1015)
E = 1.988 × 10–18 J
(ii) Energy (E) of a photon having wavelength (λ) is given by the expression,

E=hc/λ

h = Planck’s constant = 6.626 × 10–34 Js

c = velocity of light in vacuum = 3 × 108 m/s
Substituting the values in the given expression of E:

E=(6.626*10-34)(3*108)/0.50*10-10=3.976*10-15 J

E=3.98*10-15 J

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