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What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?

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Energy (E) of a photon = hν
Energy (En) of ‘n’ photons = nhν

Where, λ = wavelength of light = 4000 pm = 4000 ×10–12 m c = velocity of light in vacuum = 3 × 108 m/s h = Planck’s constant = 6.626 × 10–34 Js
Substituting the values in the given expression of n:

Hence, the number of photons with a wavelength of 4000 pm and energy of 1 J are
2.012 × 1016.

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