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in Physics by (61.2k points)

A farmer moves along the boundary of a square field of side 10 m in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?

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A farmer moves along the boundary of a square field of side 10 m in 40s
2 minutes 20 seconds means 140 seconds.
Distance travelled by farmer
\(\frac{40}{40}\) × 140 m
= 140 m.
∴ Farmer moves for 2 minutes 20 seconds. It means \(\frac{140}{40}\) = 3.5 rounds
From the original point, he moves for 2 minutes 20 seconds.
Case i) Original point means any point in the corner of the field. In this case he moves for 2 min 20 seconds from the diagonal of the field.
Displacement is equal to diagonal of the field displacement
\(\sqrt{10^2+10^2}\)
= 14.1 m.
Case ii) Original point means any point in the middle of the side of the field.
∴ Displacement is equal to any side of the field = 10 m.
It means displacement is between any original point i.e., in between 14.1 m and 10 m.

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