Initial velocity of the bus u = 80 kmh-1
80 x \(\frac{5}{18}\) = 22.22 m/s
60 x \(\frac{5}{18}\) = 16.66 m/s
Final velocity, V = 60 km/h
time taken to decrease the velocity of bus, t = 5 seconds
acceleration, a = 5 seconds
Velocity a = \(\frac{v-u}{t}\)
= \(\frac{16.66-22.22}{5}\)
= -1.112 ms-2.
