Initial velocity of a racing car, u = 0 (at rest)
acceleration, a = 4 m/s2
time t = 10 s
As per second law of motion
S = ut + \(\frac{1}{2}\)at2
Here S means distance travelled by car after 10s
S = 0 + \(\frac{1}{2}\) x 4 x (10)2
= \(\frac{400}{2}\) = 200 m
∴ Distance covered by car after 10s = 200 m
