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A stone is thrown in vertically upward direction with a velocity of 5ms-1 If the acceleration of the stone during its motion is 10ms-2 in the downward direction, what will he the height attained by the stone and how much time will it take to reach there?

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Initial velocity of a stone, u = 5 ms-1.

Final velocity of a stone v = 0 (at rest)

If the acceleration of the stone during its motion is = -10ms-2.

Let the maximum height be ‘s’

v = u + at

0 = 5 + (-10)t

t = \(\frac{-5}{10}\) = 0.5s

time taken by stone = 0.5s

As per 3rd Law of motion

v2 = u2 + 2as

(0)2 = (5)2 + 2(-10)s

∴ S = \(\frac{5^2}{20}=\frac{25}{20}\) = 1.25 m

Height attained by the store = 1.25 m.

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