Let number of machines be ‘x’ machines
When cost of one machine decreases = 200 – 50 = 150Rs
Cost (Rs) |
200 |
150 |
No. of machines |
75 |
x |
We know k = xy
200 × 75 = 150 × x
x = (200×75)/150
= 100
∴ Raghu can buy 100 machines when he gets a discount of Rs 50 on each machine.