Mass of object m_{1} = 1 Kg,

Velocity, u_{1} = 10ms^{-1}

Mass of wooden block m_{2} = 5Kg,

velocity u_{2} = 0 (since wooden block is rest)

= 1 × 10 + 5 × 0 = 10 Kgms^{-1}

According to law of conservation of momentum

Momentum after impact = Momentum before impact

(m_{1} + m_{2})v = 10

Where v = velocity of combined object

(1 + 5) v = 10

v = \(\frac{10}{6}\) = 1.67ms^{-1}.