# An object of mass 1Kg travelling in straightline with a velocity of 10ms^-1 collides with, and sticks to, a stationary wooden

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An object of mass 1Kg travelling in straightline with a velocity of 10ms-1 collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straightline. Calculate the total momentum just before the impact and just after the impact Also calculate the velocity of the combined object.

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Mass of object m1 = 1 Kg,
Velocity, u1 = 10ms-1
Mass of wooden block m2 = 5Kg,
velocity u2 = 0 (since wooden block is rest)
= 1 × 10 + 5 × 0 = 10 Kgms-1
According to law of conservation of momentum
Momentum after impact = Momentum before impact
(m1 + m2)v = 10
Where v = velocity of combined object
(1 + 5) v = 10
v = $\frac{10}{6}$ = 1.67ms-1.