Height of a cone, h = 20 cm.
Vertical angle = 60°
Diameter of frustum wire = \(\frac{1}{16}\)cm.
(i) In ⊥∆AQC, ∠Q = 90°
(ii) In ⊥∆PRA, ∠R = 90°
Height of frustum, h = 10 cm.
∴ Volume of metallic frustum, ABCD,
Let the length of wire which has diameter \(\frac{1}{16}\)cm be ‘x’ cm
∴ Length of wire = 7964.4 m