**Here is Reaction with Balance**

10FeC_{2}O_{4} + 6KMnO_{4} + 24H_{2}SO_{4} ----> 3K_{2}SO_{4}+ 6MnSO_{4} + 5Fe_{2}(SO_{4})_{3} + 24H_{2}O + 20CO_{2}

So we see that

6 moles of KMnO_{4} is required to oxidize 10 moles of FeC_{2}O_{4}

Then, 1 mole of FeC_{2}O_{4} would be oxidized by = ?

6/10=0.6