(i) PQ Bisects AB at R.
∠PRA and ∠ARS are on straight line PQ.
∴ ∠PRA + ∠ARS = 180°
Adjacent angles
50 + ∠ARS = 180°
∠ARS = 180 – 50
∴ x = ∠ARS = 130° (i)
(ii) Similarly, PQ straight line intersects straight line CD at S.
∴∠CSQ = ∠RSD .
Vertically opposite angles
∴y = ∠RSD = 130° (ii) From (i) and (ii),
∠ARS = ∠RYD
x = y = 130°
(iii) These are mutual alternate angles
∴x = y = 130°
∴ AB || CD.