In this figure,
∠X = 62°
∠XYZ = 54°
In ∆XYZ, YO and ZO are angular bisectors of
∠XYZ and ∠XZY.
Then, ∠OZY = ? ∠OYZ = ?
In ∆XYZ
∠X + ∠Y + ∠Z = 180°
62 + 54 + ∠Z= 180
116 + ∠Z= 180 ∠Z= 180- 116
∴ ∠Z = 64° YO is the angular bisector of ∠Y
∴ ∠OYZ = = 27°
ZO is the angular bisector of ∠Z
∴ ∠OZY = = 32°
∴ ∠OZY = 32°
Now, in ∆OYZ,
∠OYZ + ∠OZY + ∠YOZ = 180°
27 + 32 + ∠YOZ = 180
59 + ∠YOZ = 180
∠YOZ = 180 – 59
∴∠YOZ = 121°
∴ ∠OZY = 32°
∠YOZ = 121°