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0 votes
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in Polynomials by (65.2k points)

What are the possible expressions for the dimensions of the cuboids whose volumes are given below : 

(i) Volume: 3x2 – 12x 

(ii) Volume: 12ky2 + 8ky – 20k

1 Answer

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Best answer

(i) length × breadth × height 

= Volume of Cuboid 

= 3x2 – 12x 

= 3x2 – 12x 

= 3x(x – 4) 

= 3 × x × (x – 4)

l × b × h 

∴ Length = 3 Breadth = x Height = (x – 4) 

(ii) length × breadth × height 

= Volume of Cuboid 

= 12ky2 + 8ky – 20k 

12ky2 + 8ky – 20k 

= 4k(3y2 + 2y – 5) 

= 4k (3y2 + 5y – 3y – 5) 

= 4k (y(3y + 5) – 1 

(3y + 5)) = 4k × (3y + 5) × (y – 1) 

l × b × h 

∴ Length = 4k 

Breadth = (3y + 5) 

Height = (y – 1)

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