Data: ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F.
To Prove: F is the mid-point of BC.
Proof: Straight line EF cuts at G.
In ∆ABD, E is the mid-point of AD (Data)
EF || AB
EG || AB
∴ G is the mid-point of BD.
∵ Converse of mid-point formula.
DC || AB and EF || AB
⇒ DC || EF
In ∆BDC,
GF || DC G is the mid-point of BD (proved)
∴ F is the mid-point of BC.