ABCD is a parallelogram.
AE ⊥ DC and CF ⊥ AD.
AB = 16 Cm, AE = 8 cm,
CF = 10 cm, then AD = ?
(i) Area of ABCD = base × altitude
= DC × AE ( ∵ AB=DC)
= 16 × 8
= 128 sq. cm.
Whether ABCD is quadrilateral,
ADCB is a quadrilateral.
∴ Area of ADCB = 128 sq. cm.
Base = AD = ?
Altitude, CF= 100 cm.
Base × Altitude = Area
AD × CF = 128
AD × 10 = 128
∴ AD = \(\frac{128}{10}\)
∴ AD = 12.8 cm.