Data: AP || BQ || CR.
To Prove: ar.(∆AQC) = ar.(∆PBR)
Proof: AP || BQ. CR is a line segment.
∆ABQ and ∆PBQ are on base BQ and in between
AP || BQ ar.(∆ABQ) = ar.(∆PBQ) ………….. (i)
∆BQC and ∆BQR are on base BQ and in between BQ || CR.
∴ ar.(∆BQC) = ar.(∆BQR) ………….. (ii)
Adding (i) and (ii),
ar.(∆ABQ) + ar.(∆BQC) = ar.(∆PBQ) + ar.(∆BQR)
∴ ar.(∆AQC) = ar.(∆PBR).