Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
7.6k views
in Equilibrium by (45 points)
edited by

500ml of 0.1M HCOOH (formic acid) is mixed with 1500ml of 0.05M H2SO4 solution calculate pH of the solution

Please log in or register to answer this question.

1 Answer

+1 vote
by (5.0k points)

In formic acid solution, millimole of COOH2 = Molarity x Volume(ml)
                                              = 0.1 x 500
                                              = 50
  So, Millimole of H+ in COOH2 = 2 x 50
In H2SO4 solution, millimole of H2SO4 = 0.05 x 1500
                                                        = 75
  So, millimole of H+ in H2SO4 = 2 x 75
Total millimole of H+ = (100+150) = 250
Total volume of mixture = 1500+500 = 2000ml.
final concentration of H+ = 250/2000
                                   0.125 M
So, final pH= -log[H+] = -log(0.125)

= 0.90

by (45 points)
Thank you so much @mukulsingh12
by (5.0k points)
Welcome

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...