Data: In cyclic quadrilateral ABCD, AC and BD are diameters of circle.
To Prove: ABCD is a rectangle.
Proof: AC is a diameter.
∠ABC is angle in semicircle.
Angle in semicircle is a right angle.
∴ ∠ABC = 90°
∠ADC = 90°
Similarly, BD is a diamgers,
∠DAB, ∠DCB are angles in semicircle.
∠DAB = 90°
∠DCB = 90°
Now, four angles of quadrilateral ABCD are right angles.
∴ ∠A = ∠B = ∠C = ∠D = 90°
∴ ABCD is a rectangle.