# Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets.

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Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm × 20 cm × 5 cm and the smaller of dimensions 15 cm × 12 cm × 5 cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs. 4 for 1000 cm2, find the cost of cardboard required for supplying 250 boxes of each kind.

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Measurement of big box, l = 25 cm.

b = 20 cm.

h = 5 cm.

∴ TSA of eacxh big box = 2(lb + bh + lh)

= 2 [25 × 20 + 20 × 5 + 25 × 5]

= 2 [500 + 100 + 120]

= 2 (725) T.S.A. =1450 cm2

For all the overlaps 5% of the total surface area is required extra.

$\frac{5}{100} \times1450$

= 72.5 cm2

∴ Total surface area of big box,

TSA = 1450 + 72.5 = 1522.5 cm2

Area required for 1 box is 1522.5 cm2

Area required for 25 boxes … ?…

= 1522.5 × 250 = 380625 cm2

Dimension of small box, l = 15 cm. b = 12 cm. h = 5 cm.

∴ TSA of each small box = 2(lb + bh + lh)

= 2 [15 × 12 + 12 × 5 + 15 × 5]

= 2 [180 + 60 + 75] = 2 × 315

= 630 cm2

More area to overlap cardboard is 5% more.

For 100 cm2 , 5 cm2

For 630 cm2 , …?… = 31.5 cm2

∴ T.S.A.= 630 + 31.5= 661.5 cm2

TSA required for 1 box is 661.5 cm2

TSA required for 250 boxes …?… = 661.5 × 250 = 165375 cm2

∴ To prepare 500 boxes, TSA = 380625 + 165375 = 546000 cm2

Cost of 1000 sq.cm, of cardboard is Rs.4 Cost of 546000 sq.cm of cardboard is ? = Rs. 2184