we have cot *x* = - √ 3

⇒ tan* x *= - 1 / √ 3

.................(1)

as we know that tan (π - θ) = - tan θ and tan (2π - θ) = - tan θ

now from (1) we get

tan *x* = tan (5π / 6) and tan *x *= tan (11π / 6)

⇒ *x* = 5π / 6 and * x* = 11π / 6

so the principal solutions are **x**** = 5π / 6 ** and ** **** x**** = 11π / 6**