Question

A well is dug 20 m deep and it has a diameter of 7 m. The earth which is so dug out is spread out on a rectangular plot 22 m long and 14 m broad. What is the height of the platform so formed?

Answer 1

We have,

Depth of well = 20m

Diameter of well = 7 m

Radius of well = d/2 = 7/2 m

Dimension of rectangular field = 22m × 14m

Volume of earth dug out from well = πr²h

= 22/7 × 7/2 × 7/2 × 20

= 770 m³

When this earth is spread on rectangular field,

Then,

∴ Height of platform formed on rectangular field = volume of earth dug out / area of field

= 770/ (22×14)

= 2.5m