==> As we know it consumes 9 secs that is completing 3 T's to cover 12A distance. In rest 1 sec according to phasor it covers (2π/3) that is 120° and thus covering :
x= A to x= 0 ----> A
and x= (A√3/2) to x= A ---> A/2(2-√3)
So the total distance covered in 10 secs == . A/2[ 28-√3 ].
HOPE IT HELPS.....