We have,
Length of cylindrical tube = 14 cm
Let outer radius of tube = R cm
Let inner radius of tube = r cm
Difference between inside and outside surface = 88 cm2
2π (R-r) h = 88 ….. (i)
Volume of cylinder = 176 cm3
π (R2 – r2) h = 176 ….. (ii)
Dividing equation (i) by equation (ii)
2π (R-r) h / π (R2 – r2) h = 88/176
2 / R + r = 1/2
R+r = 4 ……. (iii)
From equation (ii)
π (R2 – r2) h = 176
π (R+r) (R-r) h = 176
22/7 × 4 × (R-r) × 14 = 176
R-r = 176×7 / 22×4×14
= 1232/1232
R-r = 1 ………….. (iv)
By adding equation (iii) and (iv)
R+r = 4
R-r = 1
2R = 5
R = 5/2 = 2.5cm
R-r = 1
r = 2.5 – 1
= 1.5cm
∴ Inner and outer radii are 2.5cm and 1.5cm