We have,
Depth of tube well = 280 m
Diameter of tube well = 3 m
Radius of well = d/2 = 3/2 = 1.5 m
Volume = πr2h
= 22/7 × 1.5 × 1.5 × 280
= 1980 m3
∴ Cost of sinking tube well at rate Rs 3.60/m3 = 1980 × 3.60 = Rs 7128
Curved surface area = 2πrh
= 2 × 22/7 × 1.5 × 280
= 2640 m2
∴ Cost of cementing its inner curved surface at rate Rs 2.50/m2 = 2.50 × 2640 = Rs 6600