Question

Two coils are wrapped around iron core whose coefficient of mutual inductance is 0.5 H. If in 10^-2 s, the value of current changes from 2 A to 3 A, then determine the induced emf in second coil.

Answer 1

Coefficient of mutual inductance
(M) = 0.5 H
Time (dt) = 10^-2 s, current (I_i) = 2A
Final current (I_f) = 3 A
Induced emf (ε) = \(-M \frac{d I}{d t}=-0.5 \times \frac{(3-2)}{10^{-2}}\)
= -0.5 × 10² = -50 volt