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in Oscillations and waves by (549 points)

Y​​​​​​1 = a​​​​​​1 sin(wt-2πx/y) and Y​​​​​​2 = a​​​​​​2​​​​​ sin (wt-2πx/y + €) is 

by (5.0k points)
Plz correct your correction
by (549 points)
sorry dada the second one will be cos not sin

1 Answer

+2 votes
by (1.7k points)
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Best answer
hey there,

● Answer -
∆x = λ(θ+π/2)/2π

● Explanation -
Given wave eqns are,
y1 = a1sin(ωt-2πx/λ) ...(1)
y2 = a2cos(ωt-2πx/λ+θ)
y2 = a2sin(ωt-2πx/λ+θ+π/2) ...(2)

Comparing (1) & (2), phase difference is
∆θ = θ+π/2

Path difference is given by -
∆x = ∆θ × λ / 2π
∆x = λ(θ+π/2)/2π

Hence, path difference is λ(θ+π/2)/2π .

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