Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
391 views
in Linear Equations by (65.5k points)

Solve the following :

i. x + 3 = 11

ii. y – 9 = 21

iii. 10 = z + 3

iv. \(\frac{3}{11} + x = \frac{9}{11}\)

v. 10x = 30

1 Answer

+1 vote
by (65.3k points)
selected by
 
Best answer

i. x + 3 = 11

x + 3 = 11 

x = 11 – 3 

x = 8

ii. y – 9 = 21

y – 9 = 21 

y = 21 + 9 

y = 30

iii. 10 = z + 3

10 = z + 3 10-3 =z 

7 = z 

or z = 7

iv. \(\frac{3}{11} + x = \frac{9}{11}\)

v. 10x = 30

10x = 30 

x = \(\frac{30}{10}\)

x = 3

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...