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Find two numbers such that one of them exceeds the other by 9 and their sum is 81.

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Find two numbers such that one of them exceeds the other by 9 and their sum is 81.

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Let number is x. 

The other number is x + 9. 

Their sum is 81 

∴ x +(x + 9) = 81 

2x = 81 – 9 

2x = 72 

x = \(\frac{72}{2}\)

x = 36 

x + 9 = 36 + 9 = 45 

∴ The number are 36 and 45

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