a) d7 means the configuration. In other words, there will be 3 unpaired electrons of a 3/2 spin.
b) The correct answer is s- orbital
- When l = 0, it is evident from that the angular momentum of the electron is zero.
- The atomic orbitals which describe these states of zero angular momentum are called s orbitals.
- The s orbitals are distinguished from one another by stating the value of n, the principal quantum number.
c) The correct option is c
After the 4s is full we put the remaining six electrons in the 3d orbital and end with 3d9. Therefore the expected electron configuration for Copper will be 1s2 2s2 2p2 3s2 3p2 4s1 3d10.
[Ar] 4s1 3d10