Question

Find the point of intersection of the straight lines 3y + 4x = 7 and 4y + 3x = 7, by drawing their graphs and looking for the point where they meet.

Answer 1

3y + 4x = 7 

3y = 7 - 4x

\(y - \frac{7 - 4x}{3}\)

When x = 1, \(y - \frac{7 - 4x}{3}\) 

= \(\frac{7 - 4}{3} = \frac{3}{3}\)  = 1

When x = 4,

The two lines intersect each other at (1, 1)