Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
964 views
in Atomic Physics by (61.1k points)

In hydrogen atom light corresponding to transition from n = 4 to n = 2 falls on a metal whose work function is 1.9 eV. Find out the maximum kinetic energy of the emitted photoelectrons.

1 Answer

+1 vote
by (57.3k points)
selected by
 
Best answer

By Einstein’s relation
E = W0 + (EK)max , W0 = Work function = 1.9 eV
hv = W0 + (EK)max, (EK)max. = Maximum K.E.
\(h \frac{C}{\lambda}\) = W0 + (EK)max.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...